Question

In triangle AB=AC and AP perpendicular to BC and angle B=60°.Then find (1) Angle B AP(2) Angle ACB

Answer 1

Answer:

         A

        /|\

     /   |   \        

B /      |     \ C

          p

We know that summation of all angles of the triangle is always 180°

So, angle A + angle B + angle C = 180°

According to the question angle B = 60

therefore,   angle A + 60° + angle C = 180°

⇒ angle A + angle C = 180° - 60° = 120°

In ABC triangle AB = AC

that means angle B = angle c

So, angle C = 60°

And angle A = 120° - 60° = 60°

Angle ACB = 60°  ..........(Answer 1)

We know the angle B which is 60°

and we calculate angle A = 60°

according to the question AP perpendicular to BC

So, 1/2 of angle A or angle BAP = 60°/2 = 30° ..........(Answer 2)

or,

angle B = 60

Angle APB = 90 because AP perpendicular to BC.

And we know that summation of all angles of the triangle is always 180°

So, angle BAP = 180° - ( 60° + 90°) = 30° ..........(Answer 2)

Answer 2

Answer:

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