in triangle ABC,1/r1+1/r2+1/r3
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Answer:1/r
Step-by-step explanation
1/R1+1/R2+1/r3
=1/∆/s-a+1/∆/s-b+1/∆/s-c
=s-a/∆+s-b/∆+s-c/∆
=s-a+s-b+s-c/∆
=3s-(a+b+c)/∆
=3s-2s/∆
=s/∆
This is the answer
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