in triangle abc 2 times angle A is equal to 3 times angle b is equal to 6 times angle C find angle A B and C of the triangle ABC
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Given:
In ΔABC 2 times ∠A is equal to 3 times ∠b is equal to 6 times ∠C
To Find:
Find ∠A, ∠B and ∠C of the ΔABC
Solution:
Let every angle be in terms of C.
So,
∠C = C
∠B = 2C (3B=6C)
∠A = 3C (2A=6C)
So, by angle sum property,
∠A + ∠B + ∠C = 180°
3C + 2C + C = 180°
6C = 180°
∠C = 30°
∠B = 60°
∠A = 90°
Hence, ∠A = 90°, ∠B = 60° and ∠C = 30° in the ΔABC.
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