In triangle ABC , 2 x angle A = 3 x angle B = 6 x angle C.
Find angle A,B and C of triangle ABC.
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Answered by
1
in triangle ABC, total angle is 180°
so
angle A+angle B+angle C=180°
x/2+x/3+x/6=180
6x/6=180
x=180
now
A is x/2
so A= 180/2
A=90
similarly you'll find all the angle
so
angle A+angle B+angle C=180°
x/2+x/3+x/6=180
6x/6=180
x=180
now
A is x/2
so A= 180/2
A=90
similarly you'll find all the angle
roovi942:
yup i just saw.....i miss the start point
Answered by
1
⭐hey there!!
Given that :
=> 2/_A = 3/_B = 6/_C = x (let)
So /_A = x/2, /_B = x/3, /_C = x/6
Now we know that,
==> sum of interior angles of ∆ = 180°
=> /_A + /_B + /_C = 180°
=> x/2 +x/3 +x/6 = 180°
=> (3x +2x + x) /6 = 180 °
=> 6x/6 = 180°
=> x = 180°
=> /_A = x/2 = 90°
=> /_B = x/3 = 60°
=> /_C = x/6 = 30°
_______________________________________
⭐Hope it will help u
Given that :
=> 2/_A = 3/_B = 6/_C = x (let)
So /_A = x/2, /_B = x/3, /_C = x/6
Now we know that,
==> sum of interior angles of ∆ = 180°
=> /_A + /_B + /_C = 180°
=> x/2 +x/3 +x/6 = 180°
=> (3x +2x + x) /6 = 180 °
=> 6x/6 = 180°
=> x = 180°
=> /_A = x/2 = 90°
=> /_B = x/3 = 60°
=> /_C = x/6 = 30°
_______________________________________
⭐Hope it will help u
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