In triangle abc, 2a=3b=6c, find angle a,b,c..
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Answered by
55
Given,
2a=3b=6c
to find:
angle a,b,c
solution:
2a=6c
a=6c/2
a=3c
3b=6c
b=6c/3
b=2c
By angle sum property of a triangle,
a+b+c=180°
Substitute (a=3c) and b=2c,
3c+2c+c=180°
6c=180°
c=180°/6
c=30°
a=3c=3×30°=90°
b=2c=2×30°=60°
c=30°
90°+60°+30°=180°
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7
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