in triangle abc 3 times angle a= 4times angle b=6times angle c find angle a ,angle b and angle c
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3a=4b=6c
let 3a=4b=6c=k
now,a+b+c=180(angle sum property)
k/3+k/4+k/6=180
lcm=12
(4k+3k+2k)/12=180
9k/12=180
k=180*12/9
=240
so a=240/3=80
b=240/4=60
c=240/640
let 3a=4b=6c=k
now,a+b+c=180(angle sum property)
k/3+k/4+k/6=180
lcm=12
(4k+3k+2k)/12=180
9k/12=180
k=180*12/9
=240
so a=240/3=80
b=240/4=60
c=240/640
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