Question

In triangle ABC,6 angle A=3 angle B=2 angle C. find the angles​

Answer 1

Step-by-step explanation:

we have a triangle ABC

let, 6 angle A =3 angle B = 2 angle C = x .…..(*)

we know the property ,

sum of interior angles of a triangle = 180 degree

therefore,

angle A + angle B+ angleC = 180 degree .........(#)

from (*)

• angle A=x/6
• angle B= x/3
• angleC= x/2

put these above equations in (#) we get

x/6+x/3+x/2=180°

x/6+2x/6+3x/6=180°

(x+2x+3x)/6=180°

6x/6= 180°

x=180°

now,

• angle A = 180°/6 = 30°
• angle B = 180°/3 = 60°
• angleC = 180°/2 = 90°

Answer 2

Answer:

∆A+∆B+∆C=180°

∆A=x/6

∆B=x/3

∆C=x/2

x/6+x/3+x/2=180°

x/6+2x/6+3x/6=180°

(x+2x+3x)/6=180°

6x/6=180°

∆A=180°/6=30°

∆B=180/3=60°

∆C=180/2=90°

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