in triangle ABC A(0,-2) B(3,1),C (-3,1) then it is which triangle
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The vertices of ΔABC are given as A(1,2,3),B(−1,0,0), and C(0,1,2).
Also, it is given that ∠ABC is the angle between the vectors BA and BC.
BA={1−(−1)}i^+(2−0)j^+(3−0)k^=2i^+2j^+3k^
BC={0−(−1)}i^+(1−0)j^+(2−0)k^=i^+j^+2k^
∴BA⋅BC=(2i^+2j^+3k^)⋅(i^+j^+2k^)=2×
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