In triangle abc, a = 9, c = 5, and b = 120. Find b2. 61 83.5 128.5 151
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Answer:
151
Step-by-step explanation:
Given
In triangle abc, a = 9, c = 5, and b = 120. Find b^2
We need to draw and observe angle 120 degree. Let A = 9 and C = 5
Using law of cosines we can find side b.
So b^2 = a^2 + c^2 – 2 x a x c x cos b
b^2 = a^2 + c^2 – 2 x a x c x cos 120
b^2 = 81 + 25 – 2 x 9 x 5 x (-1/2)
b^2 = 81 + 25 + 45
b^2 = 151
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