In triangle abc a b bisect of triangle A B C respectively if triangle ABC is equal to 32 degree triangle ABC b is equal to 58 find triangle ABC and in triangle angle BOC
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Let the ∠OBC=x and ∠OCB=y
∠BOC=180−(x+y)
Exterior ∠BOC=360−(180−(x+y)=180+(x+y)
For the quadilateral ABOC, we have
32+180+(x+y)+x+y=360
2(x+y)=148
(x+y)=74
∠BOC=180−74=106°
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