in triangle abc a b equal to BC and BD equal to 64 degree find angle C
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Answer:
∠C = 58°
Step-by-step explanation:
We can see that ∠A = ∠C [∵AB=AC]
∠A +∠C + ∠B = 180∘ {∵ sum of all the angles of triangle is 180o}
so, 2∠C = 180∘ - 64∘= 116∘ (since ∠A = ∠C)
⇒∠C = 2116∘ =58∘
⇒∠A = 58∘ and ∠C = 58∘
⇒∠C = 58∘
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