Question

In triangle ABC ,a circle is circumscribed and BD bisect angle ABC in triangle ABC prove that AB/BD=BE/BC​

Answer 1

Answer:

As tangents drawn from an external point to a circle are equal in length.

So, therefore, we get AP=AQ (tangents from A)

BP=BR (tangent from B)

CQ=CR (tangent from C)

It is given that ABC is an isosceler triangle with sides AB=AC

⇒AB−AP=AC−AP

⇒AB−AP=AC−AQ

⇒BR=CQ

⇒BR=CR

So, therefore, BR=CR that imples BC is bisected at the point of contact.

Step-by-step explanation:

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