Question

in triangle ABC a line parallel to BC, meet AB and AC at D and E. AE=4.5, AD=2, DB=5, find EC?​

Answer 1

Answer:

11.25 cm

Step-by-step explanation:

As BC is parallel to ABC, $AD:DB::AC:EC$ according to Basic Proportionality Theorem.

$\frac{2}{5}=\frac{4.5}{EC}\\EC=4.5\times \frac{5}{2}\\EC = 11.25 cm$

Answer 2

answer is attached.. with figure