Question

in triangle ABC,A-P-B and A-Q-C such that she PQ|| side BC and seg PQ divides triangle ABC in two parts whose areas are equal. find the value of BP÷AB

Answer 1

Answer:

Step-by-step explanation:

Here in triangle x b y and triangle ABC

Angle b = Angle b....common

Angle x y z = angle ACB ....

corresponding angle

Triangle x b y congruent to triangle abc by angle angle similarity.

Triangle abc /triangle x b y =a b square by XB....1

Area of triangle ABC equals to 2 triangle x b y

Area of triangle abc by area of triangle x b y equals to 2 by 1 ....2

From equation 1 and 2

AB b y x b square equals to 2 by 1

Equals to 1 by x b equals to root over 2 by 1

XB buy a b equals to 1 by root 2 equals to 1 - x b by a b equals to 1 - 1 by root 2

a b minus x b by a b equals to root 2 minus 1 by root 2 equals to a x by a b = 2 root 2 minus one by root 2 equals to 2 minus root 2 by 2

Hope it helps ...