in triangle ABC, a²sin2C+c²sin2A =?
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Step-by-step explanation:
Given In triangle ABC, a²sin2C+c²sin2A =?
- So we have a^2 sin 2C + c^2 sin 2A
- We can write this as
- 2a. (a sin C) cos c + 2c (c sin A) cos A
- We have a/sinA = b/sin B = c / sin C
- So we have a sin C = c sin A
- So 2a c sin A cos C + 2c. A sin C .cos A
- Taking 2ac as common we get
- So 2ac. Sin (A + C)
- Now in any triangle sum of angles = 180
- So A + B + C = π
- Or A + C = π – B
- So 2ac. Sin (π – B)
- Or 2ac. Sin B
- We can write this as
- 2 x 2 x ½ ac sin B
- 4 Δ
Reference link will be
https://brainly.in/question/1942105
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