Question

In triangle ABC,AB=10cm,BC=6.5cm,and ABC=90.Find ACB.
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Answer 1

Step-by-step explanation:

• Perpendiculer = 10 unit
• Base = 6.5 unit

To Find : Hypotenuse =?

Solution:-

Hypotenuse^2= perpendiculer^2+ base^2

${(ac)}^{2} = {(ab)}^{2} + {(bc)}^{2} \\ {(ac)}^{2} = {(10)}^{2} + {(6.5)}^{2} \\ {(ac)}^{2} = 100 + 42.25 \\ {(ac)}^{2} = 142.25 \\ ac = \sqrt{142.25} \\ 11.92umit \\ 12approx$