In triangle ABC, AB = 12cm, AC = 7cm and BC = 10cm. If sides AB and AC are doubled while BC remains the same, then find the area of triangle?
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AB = 12cm, AC = 7cm and BC = 10cm.
If sides AB and AC are doubled, AB becomes = 24cm, AC becomes = 14cm
while BC remains the same = 10cm
Using Heron's formula
s = (24+14+10)/2 =24
Area = root 24(24-24)(24-14)(24-10)
= root 24(0)(10)(14)
= 0
The new triangle will have no area
NOTE
The sum of the two shorter sides = the longer side
If sides AB and AC are doubled, AB becomes = 24cm, AC becomes = 14cm
while BC remains the same = 10cm
Using Heron's formula
s = (24+14+10)/2 =24
Area = root 24(24-24)(24-14)(24-10)
= root 24(0)(10)(14)
= 0
The new triangle will have no area
NOTE
The sum of the two shorter sides = the longer side
joshsol123:
Thanks but the question was wrong
Answered by
2
Answer:
Step-by-step explanation:
AB = 12cm, AC = 7cm and BC = 10cm.
If sides AB and AC are doubled, AB becomes = 24cm, AC becomes = 14cm
while BC remains the same = 10cm
Using Heron's formula
s = (24+14+10)/2 =24
Area = root 24(24-24)(24-14)(24-10)
= root 24(0)(10)(14)
= 0
The new triangle will have no area
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