Question

In triangle ABC, AB = 12cm, AC = 7cm and BC = 10cm. If sides AB and AC are doubled while BC remains the same, then find the area of triangle?

Answer 1

AB = 12cm, AC = 7cm and BC = 10cm. 

If sides AB and AC are doubled, AB becomes = 24cm, AC becomes = 14cm

 while BC remains the same = 10cm

Using Heron's formula

s = (24+14+10)/2 =24

Area = root 24(24-24)(24-14)(24-10)

        = root 24(0)(10)(14)

         = 0

The new triangle will have no area


NOTE

The sum of the two shorter sides = the longer side

Answer 2

Answer:

Step-by-step explanation:

AB = 12cm, AC = 7cm and BC = 10cm.

If sides AB and AC are doubled, AB becomes = 24cm, AC becomes = 14cm

while BC remains the same = 10cm

Using Heron's formula

s = (24+14+10)/2 =24

Area = root 24(24-24)(24-14)(24-10)

= root 24(0)(10)(14)

= 0

The new triangle will have no area