Question

In triangle ABC, AB =
20 a+b = 40 cm find a and b​

Answer 1

AB+BC−AC=20(E01)

Perimeter : AB+BC+AC=60(E02)

(E01)+(E02):2(AB+BC)=80⟹BC=40−AB

(E02)−(E01):2(AC)=40⟹AC=20

From △ABC:AC2=AB2+BC2⟹202=AB2+(40−AB)2

⟹400=2AB2+1600−80AB⟹AB2−40AB+600=0

Δ:402−4(600)=−800<0

⟹No real solution for AB. Hence no triangle can be formed.

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