Question

In triangle ABC, AB = 20 cm ,BC = 16 cm and its semiperimeter is 25 cm.What is the

length of AC ?​

Answer 1

Step-by-step explanation:

• (AB)²+(BC)²=(AC)²
• 20²+16²=(AC)²
• 400+256=AC²
• 656=AC²
• AC=√656
• AC= 25.61cm

Answer 2

Answer:

14

Step-by-step explanation:

AB=20

BC=16

Let AC=x

semiperimeter= 25

= (20+16+x)/2=25

= 36+x=25×2

= x= 50-36

x= 14

AC = 14

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hope it's correct