In triangle abc ab =25 and angle c = 45 find the bc
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Answer:
Let ABC a triangle
The angle@B
By Pythagoras theorem
hypotenuse^2= base^2+height^2
(AC)^2= (AB)^2+(BC)^2
(45)^2= (25)^2+(BC)^2
2025= 625+ BC^2
2025-625 = BC^2
1400= BC^2
BC=√1400
BC=37.41
HOPE IT HELPS YOU!!!!!
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