Question

In triangle ABC, AB=4cm, altitude CF=6cm and AC=3cm.Find the length of altitude BE

Answer 1

Answer:

$area \: of \: triangle = 0.5\times b \times h$

BASE - 4 cm

HEIGHT - 6 cm

= 0.5× 4×6

=2×6

=12 cm²

HOPE IT HELPS

Answer 2

Answer:

$area = \frac{1}{2} \times base \times height. \\ 12 = \frac{1}{2} \times 5 \times be. \\ 5 \times be = 2 \times 12 = 24. \\ be = \frac{24}{5} = 4.8cm.$