Question

in triangle ABC AB=6 cm, BC=7cm and AC=5 cm. The area of triangle ABC i​

Answer 1

Answer:

4$\sqrt{3}$ $cm^{2}$

Explanation:

Area of a triangle = $\sqrt{s(s-a)(s-b)(s-c)}$ where S is the semi-perimeter.

Perimeter = (6+7+5) cm = 18 cm        

So, semi-perimeter = (19/2) cm = 8 cm

So, area = $\sqrt{8(8-6)(8-7)(8-5)}$ $cm^{2}$

              = $\sqrt{8*2*1*3}$ $cm^{2}$

              =  $\sqrt{48}$ $cm^{2}$

              =  4$\sqrt{3}$ $cm^{2}$

Hope it helps....

Mark my answer as the brainliest.