Question

In triangle ABC, AB = 6 cm, BC = 8 cm and AC = 10 cm from B perpendicular is drawn on AC to cut at D then find area of triangle ADP+ triangle BPC​

Answer 1

Step-by-step explanation:

so area of our triangle is 24units

ok let X be the point on AB and let Y be the point on BC

let we call length of BX as m and length of XY as n

so now as i have claimed that angle C should be right angle

so we have

tanB=ACBC=nm

68=nm

n=m68

n=m34

also area of triangle BXY = 12mn

24/2= 12mn

so nm = 24

m34∗m=24 // as n=m34

m2=24∗43

m2=32

m=42–√

so BX is 42–√

// i hope i am not wrong but i hope method is clear