Question

IN TRIANGLE ABC AB = 6CM AND DE II BC SUCH THAT AE = 1/4 AC THEN WHAT IS AD ?​

Answer 1

Answer:

AD = 1.5 cm

Step-by-step explanation:

Consider ΔABC and DE║BC,  AB = 6cm, let AC = x the AE =  

Consider ΔABC and ΔADE

∠ABC= ∠ADC (corresponding angles are equal as  DE║BC)

∠BAC = ∠DAC (common angle)

Since, two angles are similar, therefore by properties of similarity of triangle,

ΔABC ΔADC

Also, if triangles are similar, their sides are in proportion,

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Answer 2

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AD = 1.5 cm

Step-by-step explanation:

Consider ΔABC and DE║BC,  AB = 6cm, let AC = x the AE =  

Consider ΔABC and ΔADE

∠ABC= ∠ADC (corresponding angles are equal as  DE║BC)

∠BAC = ∠DAC (common angle)

Since, two angles are similar, therefore by properties of similarity of triangle,

ΔABC ΔADC

Also, if triangles are similar, their sides are in proportion,