In triangle ABC, AB=7 , BC= 5 , AND AC= 2 sqrts of 6, C is the right angle, how do you find measure of angle B?
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Answer:
Step-by-step explanation:
tanB=AC/BC
=2√6/7
=2*2.449/7
=0.699
B=arctan(0.669)
=33.78°
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