Question

in triangle ABC, AB=7cm, BC=8cm and AC=9cm. find the value of radius of inner circle of triangle

Answer 1

Answer:

Radius = √5 cm

Step-by-step explanation:

a = 7 cm

b = 8 cm

c = 9 cm

$area = \sqrt{s(s - a)(s - b)(s - c)} \\ s = \frac{a + b + c}{2} \\ s = \frac{7 + 8 + 9}{2} = \frac{24}{2} = 12 \\ \\ area = \sqrt{(12)(12 - 7)(12 - 8)(12- 9)} \\ = \sqrt{(12)(5)(4)(3)} = 12 \sqrt{5}$

Area = radius of circle inside the triangle × s

12√5 = r × 12

r = √5

Answer 2

Answer:

This is your answer...

Step-by-step explanation:

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