In triangle ABC, AB = 8 √ 3 cm, AC = 16 cm, BC =8 cm. Find measure of ∠A
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Given :
ABC is a right angled triangle.
Angle, B = 90°
AB= 8cm
BC=15 cm.
Let the ra8dius of the incircle be, r.
r=A/s
Where A=area of the triangle.
s= semi perimeter
A=15x8/2 =60 cm.
s= (AB+ BC + CA)/2
Here AB, BC are given. CA is to be found out.
CA= √(AB^2+BC^2)= √(8^2+15^2)
√(64+225)=17
Therefore, s= ( 8+15+17)/2=20
r = A/s = 60/20=3 cm.
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Answer:
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