In triangle ABC, AB=8cm,
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FIND OC
By Phythagoras theorem,
In △ABO,AB2=AO2+BO2.....(1) and
In △ACO,AC2=AO2+OC2.....(2)
Subtracting equation 2 from 1, we get,
AB2−AC2=AO2−AO2+BO2−OC2
⇒AB2−AC2=BO2−OC2
⇒82−32=(BC+OC)2−OC2
⇒55=(BC+OC)2−OC2
⇒55=BC2+OC2+2BC×OC−OC2
⇒55=62+2×6×OC
⇒55−36=12×OC
⇒12×OC=19
⇒OC=19÷12=1.583∼1.6cm
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