Question

in triangle abc ab=8cm ac=10cm pq=2cm find ar of aqp andar of pbcq:ar of abc

Answer 1

Answer:

Expert Answer:

side BC = begin mathsize 12px style square root of A C squared minus A B squared end root space equals space square root of 10 squared minus 8 squared end root space equals space 6 space c m end style

Since triangles AQP and ABC both are right triangles and begin mathsize 12px style angle end styleA is common for both, they are similar triangles.

Hence begin mathsize 12px style fraction numerator A B over denominator A Q end fraction space equals space fraction numerator B C over denominator P Q end fraction equals fraction numerator A C over denominator A P end fraction end style

since (BC/PQ) = 3, we have AQ = (8/3) cm

Area of Δ APQ = (1/2)×AQ×QP = (1/2)×(8/3)×2 = (8/3) cm2