Question

In triangle ABC, AB = AC = 15 cm and BC = 18 cm, find
Cos b
Sin c
Tan² b - sec² b +2

Answer 1

Answer:

cos b=15/18=5/6

sin c= 15/18=5/6

tan²b-sec²b+2 =(15/15)²-(18/15)²+2

= 225/225 - 324/225 +2

= 225-324/225 +2

= -99/225 +2

= -11/25 +2

= -11+50/25

= 39/25