in triangle abc ab=ac=15cm and bc=18cm find cos b
sin c
Answers
Answered by
0
Answer:
AB=AC=15
BC=18
CosB= b/h = BC/AC
18/15 = 6/5
SinC = p/h = AB/AC
15/15 = 1
Answered by
0
Answer:
cos b = 6/5
sin c = 1
Step-by-step explanation:
cos b =adjacent side/hypotenuse = AB/BC = 18/15 = 6/5
sin c = opposite side/hypotenuse = AB/AC = 15/15 = 1
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