Question

in triangle ABC ,AB=AC=15cm and BC=18cm. find the value of tan ^2 B -sec^2 B +2​

Answer 1

tan = 18/15

sec = 15/15

this is the answer

Answer 2

Answer:

Answer:

\begin{gathered}ac^{2} = ab^{2} + bc^{2} \\ 12 ^{2} = ab ^{2} + 6^{2} \\ 144 = ab ^{2} + 36 \\ 144 - 36 = b^{2} \\ 108 = ab^{2} \\ ab = \sqrt{108 } \\ ab = 54 \: \\\end{gathered}

ac

2