Question

In Triangle ABC,AB=AC, ∟A:∟B=4:3,Find the value of ∟C. *

Answer 1

Step-by-step explanation:

In triangle ABC , AB= AC where angle ACB = angle ABC

GIVEN angle A : angle B = 4: 3

Let x be the common ratio

so, angle BAC= 4x and angle ABC and angle ACB = 3x

since, sum of the angles of a triangle is 180 degree

therefore , 4x+ 3x + 3x= 180 degree

or, 10x= 180 degree

or, x= 18 degree

therefore , angle ACB= 3x = 3X18 degree= 54 degree

Answer 2

Given : In Triangle ABC AB=AC,

∠A : ∠B = 4 : 3

To Find : value of  ∠C​

Solution:

In Triangle ABC,AB=AC,

∠B = ∠C    angles opposite to equal sides are equal )

Let say ∠A  = 4x

then ∠B = 3x   as   ∠A : ∠ B = 4 : 3

∠C   =  ∠B = 3x

∠A +  ∠B + ∠C = 180°

=> 4x + 3x + 3x = 180°

=> 10x = 180°

=> x = 18°

∠C   =   3x

=> ∠C   = 3(18) = 54°

Value of  ∠C = 54°

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