Question

In triangle ABC, AB = AC.A circle is drawn with one of these sides as diametre.Prove that the circle

biscts the side BC​

Answer 1

Answer:

Given: △ABC is an isosceles triangle with AB = AC. A circle is drawn taking AB as diameter which intersects the side BC at D

To prove: BD = DC

Construction: Join AD

Proof: ∠ADB=90

o

[Angle in a semi-circle is right angle]

∠ADB+∠ADC=180

o

⇒∠ADC=90

o

In △ABD and △ACD

AB=AC [Given]

∠ADB=∠ADC

AD=AD [Common]

∴△ABD≅△ACD [RHS congruence criterion]

So,

BD=DC [By CPCT]

solution

Answer 2

Step-by-step explanation:

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