In triangle ABC AB = AC and ab : BC = 2 : 1 and perpendicular to BC then show that 4A^2 =15 B^2
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in which AB = AC = 15 cm, and BC = 8 cm. The foot of the perpendicular from BC to A is point M. a She says that the length of BM = 4 cm. ... Write down the vectors a 5a [1] b −2b [ 1] c 3c [1] d a − b [2] e b − a [2] f a + b − c [2] g 4a + 2c [2] h c − 12a [2] i a2 + b3
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