Question

In triangle ABC, AB=AC and AD is perpendicular to BC, BE is perpendicular to AC and CF is perpendicular to AB. About which side is triangle ABC symmetrical.

Answer 1

Answer:

ΔABC is symmetrical around AD.

Step-by-step explanation:

Between ΔABD and ΔACD:

AD is common side, AB = AC [Given]

∠ADB = ∠ADC [Given that AD ⊥ BC]

∴ ΔABD and ΔACD are congruent.

∴ ΔABC is symmetrical around AD.  

Answer 2

Answer:

⇒ It is given that in △ABC, AB=AC.

∴ △ABC is an Isosceles triangle.

⇒ And in isosceles triangle line of symmetry is one.

⇒ AD⊥BC, AD divides △ABC equally.

∴ △ABC is symmetrical about AD.

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