Question

in triangle ABC ,AB=AC and angel B =2/5 of angel A . find the measure of A​

Answer 1

Step-by-step explanation:

AB = AC Given ∠ B = ∠ C Since angle opposite to equal sides are equal ∠ B = 2 5 ∠ A ⇒ ∠ B = ∠ C = 2 5 ∠ A Now , ∠ A + ∠ B + ∠ C = 180 ° Angle Sum Property ∠ A + 2 5 ∠ A + 2 5 ∠ A = 180 ° 5 ∠ A + 2 ∠ A + 2 ∠ A 5 = 180 ° 9 ∠ A = 900 ° ∠ A = 100 ° Measure of angle A is 100 ° .

Answer 2

AB = AC Given ∠ B = ∠ C Since angle opposite to equal sides are equal ∠ B = 2 5 ∠ A ⇒ ∠ B = ∠ C = 2 5 ∠ A Now , ∠ A + ∠ B + ∠ C = 180 ° Angle Sum Property ∠ A + 2 5 ∠ A + 2 5 ∠ A = 180 ° 5 ∠ A + 2 ∠ A + 2 ∠ A 5 = 180 ° 9 ∠ A = 900 ° ∠ A = 100 ° Measure of angle A is 100 ° .

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