in triangle abc ,ab=ac and angle a:angle b= 8:5 find the angles
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Since, AB = AC,
∠ACB = ∠ABC, i.e., ∠C = ∠B (Angles opposite to equal sides of a triangle are always equal.)
Let ∠A = 8x° and ∠B = 5x°
Therefore, ∠C = ∠B = 5x°
Now, ∠A + ∠B + ∠C = 180°
or, 8x° + 5x° + 5x° = 180°
or, 18x° = 180°
or, x° = 10°
Hence, ∠A = 80°
∠B =50°
∠C = 50°
Answered by
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Answer:
angle a =50 , angle b=50 ,angle c=80
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