In triangle ABC,AB=AC and angleA = 40°.The bisector from angle B intersects AC at point D .What is angle BDC
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In Δ ABD and Δ BDC
1) BD is common side
2)∠ DBA = ∠ DBC ( BD is the bisector of∠B )
3) AD =DC ( D is the midpoint of AC.)
∴Δ ABD ≅Δ BDC ( SAS congruency)
∴∠ADB =∠ BDC
As BD is the bisector of ∠B , BD is perpendicular on AC and D is the midpoint of AC.
∴∠ ADB =∠ BDC = 90°
Ans :-The angle BDC will be 90°
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