in triangle ABC, AB=AC and angleB=50 then find angle A
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for isoceles two side is same so two angle will be same .
Angle B=Angle C =50
so Angle A+Angle B+AngleC =180 for
now Angle A+50+50=180
so Angle A=80
Angle B=Angle C =50
so Angle A+Angle B+AngleC =180 for
now Angle A+50+50=180
so Angle A=80
spppp:
right
Answered by
1
Answer:
In △ABC, AB=AC
⇒angleB=angleC=50degree
By the sum property of the triangle-
angleA+angleB+angleC=180degree
angleA+50+50=180degree
angleA=(180-100)degree=50degree Ans.
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