Question

In triangle ABC, AB=AC And BD = DC where D is a point on BC, then find ADB.​

Answer 1

Answer:

In △ABD,

∠ADB+∠A+∠ABD=180o

⇒∠ADB+36+36=180o

⇒∠ADB=180−72=108o

In an isosceles triangle , opposite to equal sides are equal. In a triangle, one side is extended, 

the exterior angle is equal to sum of interior opposite angles

Answer 2

see ur answer it's down ⏬⏬⏬⏬⏬⏬⏬⏬⏬⏬⏬⏬⏬⏬⏬⏬⏬⏬⏬⏬⏬⏬Given=> AB=AC

BD=DC

Construction => Join AD

To prove that => angle ABD = angle ACD

Proof=> In triangle ADB & ADC

AD=AD [Common]

BD=CD [Given]

AB=AC [Given] Triangle ADB is congruent to Triangle ADC.

Therefore,

Angle ABD = Angle ACD [ C.P.C.T ]

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