Question

In triangle ABC, AB=AC and BD perpendicular to AC , Prove that BD^+CD^=2AC.CD​

Answer 1

ANSWER:-------------

BC2 = AB2 -

AD2 + CD2

 ⇒ BC2 = AB2 -

.

(AC - CD)2 + CD2

⇒BC2 = AB2 -

AC2 - CD2 + 2AC.

CD + CD2⇒ BC2

= 2AC. CD [Given,

AB = AC. ⇒

[]AB2 = AC2[]

Hence Proved :)

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