Question

In triangle ABC, AB=AC and D is a point on side AC such that BC2=AC*CD. Prove that BD=BC

Answer 1

Hey ! Frnd . your answer is below. I hope it helps.

Answer 2

BC2= AC.CD
BC.BC=AC.CD
BC/CD=AC/BC
ALSO C= C ( COMMON ANGLES)
∆ACB ~ ∆ BCD ( SAS SIMILARITY
AC/BC= AB/BD
AC/BC=AC/BD (AS AB = AC)
1/BC=1/BD
BC=BD