Question

In triangle ABC, AB=AC and line AO divedes the base BC into equal parts. Prove that AOB congruent AOC. ​

Answer 1

Consider triangle ABO and ACO

AB = AC (Given)

BO = OC (Given)

AO = AO (Given)

Hence, by SSS property ABO congruent to triangle ACO.

Therefore,

∠AOB= ∠ AOC

Hence,proved.

Answer 2

Step-by-step explanation:

conseder the triangle AOB and AOC

AB=AC {Given}

BO=OC {Given}

AO=AO {Common}

By sss criterion AOB congruent to AOC

therefore<AOB=<AOC {BY CPCT}

HENCE PROVED

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