Question

In triangle ABC, AB=AC and line AO divides the base BC into equal parts.Prove that ∆AOB ~=∆AOC​

Answer 1

Answer:

You can Prove it easily

Step-by-step explanation:

AB=AC (Given)

AO=AO (Common)

Angle ABO= Angle ACO (Angles opposite to equal sides are equal)

Answer 2

Answer:

BO = CO

Angle boa = angle coa

AO = AO ( COMMON SIDE )

Step-by-step explanation:

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