Question

in triangle ⛛ ABC AB=AC and the bisector of angle ABC and angle ACB meet AC and AB at D and E respectively prove that BD=CE

Answer 1

In triangle EBC and DBC
BC is equal to BC (common side)
EB is equal to DC (they are mid points)
angle EBC is equal to DCB
therefore triangle EBC is congruent to DBC
BD is equal to EC ( CPCT )

Answer 2

Answer:

This is the answer of the question