Question

In triangle ABC AB=AC, angle C = 65 degree, find angle A

Answer 1

if AB=AC and angle c=65 degree
then,
angle C=angle B (if opposite sides are equal in a triangle then its opposite angle will also be equal)
hence,angle B=65 degree
now,angle A
A+B+C=180
A+65+65=180
A+130=180
A=180-130
A=50
hence,angle A=50

Answer 2

Since AB is equal to AC
Angle C = angle B
=> by angle sum property of Triangles
Angle A+angle B+angle C = 180 (let angle A be x)
x + 65 + 65 = 180
x = 180 - 130
x = 50
Therefore angle A is 50°

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