in triangle ABC , AB =AC , anlgle BAC =50°,now CB is extended to D , then the external angle at angle DAB is
a) 90°
b) 70°
c) 115°
d) 80°
Answers
Answered by
2
Answer:
(c)115°
Step-by-step explanation:
As AB=AC
angle ABC=angle ACB (angles opposite to equal sides are equal)
angle BAC=50°(given)
angle ABC + angle BAC + angle ACB=180°(ASP)
2angleABC+50°=180°
2angleABC=130°
angle ABC=130°/2
angle ABC=65°
Similarly, angle ACB=65°
angle ABC+angle DAB=180°(exterior angle property)
angle DAB =180-65
angle DAB = 115°
answer
plz mark as brainliest
Answered by
0
Answer:
this is the right answer
Attachments:
Similar questions