in triangle abc.Ab=Ac.Bc is produced to D.E is any point on Ab.Ed is joined intersecting Ac at F.Prove Af>Ae
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3
Answer:
As, AB=BE
B is mid point of AE
Consider △EAD
From midpoint Theorem
BM=21AD (AsAD∥BM) & B is mid point of AE
⇒=21BC (As AD = BC for parallelogram)
⇒ M is midpoint of BC
Hence ED bisects BC
Answered by
1
Step-by-step explanation:
REF.Image.
As, AB=BE
B is mid point of AE
Consider △EAD
From midpoint Theorem
BM=
2
1
AD (AsAD∥BM) & B is mid point of AE
⇒=
2
1
BC (As AD = BC for parallelogram)
⇒ M is midpoint of BC
Hence ED bisects BC
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