Question

In triangle abc, ab=ac, cone a=x+15°, cone b=2x+25°,then value of cone c ?

Answer 1

Step-by-step explanation:

It is an isosceles triangle. thus ,

In ΔABC, AB = AC, ∠A = x + 15°, ∠B = 2x + 25°

It is an isosceles triangle, ∴∠B = ∠C = 2x + 25°

Sum of interior angles of Δ = 180°

⇒ x + 15° + 2x + 25° + 2x + 25° = 180°

⇒ 5x + 65° = 180°

⇒ 5x = 115°

⇒ x = 23°

∠C = 2x + 25° = 2 × 23 + 25 = 71°

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